Abstract.
The pebbling number of a graph G, f(G), is the least m such that, however m pebbles are placed on the vertices of G, we can move a pebble to any vertex by a sequence of moves, each move taking two pebbles off one vertex and placing one on an adjacent vertex. It is conjectured that for all graphs G and H, f(G×H)≤f(G)f(H).¶Let C m and C n be cycles. We prove that f(C m×C n)≤f(C m) f(C n) for all but a finite number of possible cases. We also prove that f(G×T)≤f(G) f(T) when G has the 2-pebbling property and T is any tree.
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Received: February 24, 1995 Revised: November 25, 1998
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Snevily, H., Foster, J. The 2-Pebbling Property and a Conjecture of Graham's. Graphs Comb 16, 231–244 (2000). https://doi.org/10.1007/PL00021179
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DOI: https://doi.org/10.1007/PL00021179