1.题目


Given an array of size n, find the majority element. The majority element is the element that appears more than ​​⌊ n/2 ⌋​​ times.

You may assume that the array is non-empty and the majority element always exist in the array.


2.解决方案


class Solution {
public:
int majorityElement(vector<int> &num) {
if(num.size() == 1){
return num[0];
}
map<int, int> myMap;
float majorPercent = num.size() / 2.0;
for(int i = 0; i < num.size(); ++i){
int key = num[i];
if(myMap.find(key) == myMap.end()){
myMap.insert(pair<int,int>(key,1));
}else{
int beforeCount = myMap[key];
++beforeCount;
myMap[key] = beforeCount;

if(beforeCount > majorPercent){
return key;
}
}

}
return 0;
}
};


思路:

用map当然是比较直线的解决方案。值作为key,出现的次数作为value。