10465 - Homer Simpson

Time limit: 3.000 seconds 

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=114&page=show_problem&problem=1406


这数据量。。枚举绝对是最快的方式了。


完整代码：

/*0.025s*/

#include<bits/stdc++.h>
using namespace std;

int main()
{
	int m, n, t, x, ans1, ans2, drink, i, k;
	while (~scanf("%d%d%d", &m, &n, &t))
	{
		if (m > n) swap(m, n);
		x = t / m, drink = -1u>>1;
		for (i = x; i >= 0 && drink; --i)///枚举
		{
			k = t - i * m;
			if (drink > k % n) drink = k % n, ans1 = i + k / n;///drinks as little beer as possible
			if (k % n == 0) ans2 = i + k / n;
		}
		if (drink) printf("%d %d\n", ans1, drink);
		else printf("%d\n", ans2);
	}
	return 0;
}