①确定分界点 mid = (l+r)/2
②递归排序left right 左右两个数组
③归并排序 合二为一
#include <iostream>
using namespace std;
const int N = 1e6+10;
int n;
int q[N], tmp[N];
void merge_sort(int q[], int l, int r)
{
if (l >=r) return;
int mid = l + r >> 1;
merge_sort(q, l, mid), merge_sort(q, mid+1, r);
int k = 0, i = l, j = mid + 1;
while(i <= mid && j <= r)
if(q[i] <= q[j]) tmp[k++] = q[i++];
else tmp[k++] = q[j++];
while(i <= mid) tmp[k++] = q[i++];
while(j <= r) tmp[k++] = q[j++];
for(i = l, k = 0; i <= r; i++, k++) q[i] = tmp[k];
}
int main()
{
scanf("%d",&n);
for(int i = 0; i < n; i++) scanf("%d",&q[i]);
merge_sort(q, 0, n-1);
for(int i = 0; i < n; i++) printf("%d ",q[i]);
return 0;
}