比如现在有一人员表(表名:peosons) 若想将姓名、身份证号、住址这三个字段完全相同的记录查询出来 select p1.* from persons p1,persons p2 where p1.idp2.id and p1.cardid = p2.cardid and p1.pname = p2.pname and p1.address = p2.address 可以实现上述效果. 几 比如现在有一人员表   (表名:peosons)
若想将姓名、身份证号、住址这三个字段完全相同的记录查询出来

select p1.* from persons p1,persons p2 where p1.id<>p2.id and p1.cardid = p2.cardid and p1.pname = p2.pname and p1.address = p2.address

可以实现上述效果.


几个删除重复记录的SQL语句


 


1.用rowid方法

2.用group by方法

3.用distinct方法

 

1。用rowid方法

据据oracle带的rowid属性,进行判断,是否存在重复,语句如下:
查数据:      select * from table1 a where rowid !=(select   max(rowid)  
     from table1 b where a.name1=b.name1 and a.name2=b.name2......)
删数据:
    delete   from table1 a where rowid !=(select   max(rowid)  
     from table1 b where a.name1=b.name1 and a.name2=b.name2......)

2.group by方法

查数据:
  select count(num), max(name) from student --列出重复的记录数,并列出他的name属性
  group by num
  having count(num) >1 --按num分组后找出表中num列重复,即出现次数大于一次
删数据:
  delete from student
  group by num
  having count(num) >1
  这样的话就把所有重复的都删除了。

3.用distinct方法 -对于小的表比较有用

create table table_new as   select distinct *   from table1 minux
truncate table table1;
insert into table1 select * from table_new;



查询及删除重复记录的方法大全

1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断



select * from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)



2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
delete from people
where peopleId in (select peopleId from people group by peopleId   having count(peopleId) > 1)
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)



3、查找表中多余的重复记录(多个字段)
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)



4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
delete from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)



5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)



(二)
比方说
在A表中存在一个字段“name”,
而且不同记录之间的“name”值有可能会相同,
现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
Select Name,Count(*) From A Group By Name Having Count(*) > 1



如果还查性别也相同大则如下:
Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1



(三)
方法一



declare @max integer,@id integer 
 
 
 

   declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1 
 
 
 

   open cur_rows 
 
 
 

   fetch cur_rows into @id,@max 
 
 
 

   while @@fetch_status=0 
 
 
 

   begin 
 
 
 

   select @max = @max -1 
 
 
 

   set rowcount @max 
 
 
 

   delete from 表名 where 主字段 = @id 
 
 
 

   fetch cur_rows into @id,@max 
 
 
 

   end 
 
 
 

   close cur_rows 
 
 
 

   set rowcount 0

方法二



"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。



  1、对于第一种重复,比较容易解决,使用



select distinct * from tableName



  就可以得到无重复记录的结果集。



  如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除



select distinct * into #Tmp from tableName 
 
 
 

   drop table tableName 
 
 
 

   select * into tableName from #Tmp 
 
 
 

   drop table #Tmp


  发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。



  2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下



  假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集

select identity(int,1,1) as autoID, * into #Tmp from tableName 
 
 
 

   select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID 
 
 
 

   select * from #Tmp where autoID in(select autoID from #tmp2)


  最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)



(四)
查询重复



select * from tablename where id in ( 
 
 
 

   select id from tablename 
 
 
 

   group by id 
 
 
 

   having count(id) > 1 
 
 
 

   )