题目:有N种物品和一个容量为V的背包。第i种物品最多有num[i]件可用,每件费用是c[i],价值是w[i]。求解将哪些物品装

入背包可使这些物品的费用总和不超过背包容量,且价值总和最大。 

 

分析:状态转移为:

多重背包问题_ci

 

题目:http://acm.hdu.edu.cn/showproblem.php?pid=2191

 

#include <iostream>
#include <string.h>
#include <stdio.h>

using namespace std;
const int N = 1005;

int dp[N];
int c[N],w[N],num[N];
int n,m;

void ZeroOne_Pack(int cost,int weight,int n)
{
    for(int i=n; i>=cost; i--)
        dp[i] = max(dp[i],dp[i-cost] + weight);
}

void Complete_Pack(int cost,int weight,int n)
{
    for(int i=cost; i<=n; i++)
        dp[i] = max(dp[i],dp[i-cost] + weight);
}

int Multi_Pack(int c[],int w[],int num[],int n,int m)
{
    memset(dp,0,sizeof(dp));
    for(int i=1; i<=n; i++)
    {
        if(num[i]*c[i] > m)
            Complete_Pack(c[i],w[i],m);
        else
        {
            int k = 1;
            while(k < num[i])
            {
                ZeroOne_Pack(k*c[i],k*w[i],m);
                num[i] -= k;
                k <<= 1;
            }
            ZeroOne_Pack(num[i]*c[i],num[i]*w[i],m);
        }
    }
    return dp[m];
}

int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        cin>>m>>n;
        for(int i=1; i<=n; i++)
            cin>>c[i]>>w[i]>>num[i];
        cout<<Multi_Pack(c,w,num,n,m)<<endl;
    }
    return 0;
}