http://help.3g.163.com/15/0908/11/B305R99R00964KAD.html

深.浅拷贝

    • copy mutableCopy NSString
    NSString *string = @"汉斯哈哈哈";// 没有产生新对象NSString *copyString = [string copy];// 产生新对象NSMutableString *mutableCopyString = [string mutableCopy];NSLog(@"string = %p copyString = %p mutableCopyString = %p", string, copyString, mutableCopyString); 
    • copy mutableCopy NSMutableString
    NSMutableString *string = [NSMutableString stringWithString:@"汉斯哈哈哈"];// 产生新对象NSString *copyString = [string copy];// 产生新对象NSMutableString *mutableCopyString = [string mutableCopy];NSLog(@"string = %p copyString = %p mutableCopyString = %p", string, copyString, mutableCopyString); 
     结论:
     
     
     
     
     注意:其他对象NSArray、NSMutableArray 、NSDictionary、NSMutableDictionary一样适用
     
     
     
     
    • copy NSObject
    HSPerson *p = [[HSPerson alloc] init];p.age = 20;p.height = 170.0;HSPerson *copyP = [p copy]; // 这里崩溃 
     崩溃:
     看崩溃信息HSPerson应该先实现:
     
    - (id)copyWithZone:(NSZone *)zone; 
     测试:
     
    #import "HSPerson.h"@interface HSPerson()@end@implementation HSPerson- (id)copyWithZone:(NSZone *)zone{    return @"汉斯哈哈哈";}@end HSPerson *p = [[HSPerson alloc] init];p.age = 20;p.height = 170.0;HSPerson *copyP = [p copy];NSLog(@"copyP: %@", copyP); 
     可以看出copyWithZone重新分配新的内存空间,则:
     
    - (id)copyWithZone:(NSZone *)zone{    HSPerson *person = [[HSPerson allocWithZone:zone] init];    return person;// 有些人可能下面alloc,重新初始化空间,但这方法已给你分配了zone,自己就无需再次alloc内存空间了//    HSPerson *person = [[HSPerson alloc] init];} HSPerson *p = [[HSPerson alloc] init];p.age = 20;p.height = 170.0;HSPerson *copyP = [p copy];NSLog(@"p = %p copyP = %p", p, copyP);NSLog(@"age = %d height = %f", copyP.age, copyP.height); 
     
     
     
     
     虽然copy了份新的对象,然而age,height值并未copy,那么:
     
    - (id)copyWithZone:(NSZone *)zone{    HSPerson *person = [[HSPerson allocWithZone:zone] init];    person.age = self.age;    person.height = self.height;    // 这里self其实就要被copy的那个对象,很显然要自己赋值给新对象,所以这里可以控制copy的属性    return person;} 
     
     
     
     
     这时你会想,有NSMutableCopying?没错,是有这货:
     
    - (id)mutableCopyWithZone:(NSZone *)zone{    HSPerson *person = [[HSPerson allocWithZone:zone] init];    person.age = self.age;    person.height = self.height;    return person;} 
     NSCopying、NSMutableCopying有啥区别?
     其实感觉没必要有NSMutableCopying,因为压根就没可变的HSPerson,但如果该对象有其他行为,可以借用NSMutableCopying实现,哈哈哈
     copy.strong
     说完深浅拷贝,理解copy.strong就轻松多了!
    • copy
    #import @interface HSPerson : NSObject@property (nonatomic, copy) NSString *name;@end NSMutableString *string = [NSMutableString stringWithFormat:@"汉斯哈哈哈"];HSPerson *person = [[HSPerson alloc] init];person.name = string;// 不能改变person.name的值,因为其内部copy新的对象[string appendString:@" hans"]; NSLog(@"name = %@", person.name); 
     property copy 实际上就对name干了这个:
     
    - (void)setName:(NSString *)name{    _name = [name copy];} 
     假设name为NSMutableString,会发生什么事?
     
    @property (nonatomic, copy) NSMutableString *name; 
     这样会挨骂哦,实际上内部还是:
     
    - (void)setName:(NSMutableString *)name{    _name = [name copy];} 
     copy出来的仍然是不可变字符!如果有人用NSMutableString的方法,就会崩溃:
     
     
     
     
    • 
    strong@property (nonatomic, strong) NSString *name; NSMutableString *string = [NSMutableString stringWithFormat:@"汉斯哈哈哈"];HSPerson *person = [[HSPerson alloc] init];person.name = string;// 可以改变person.name的值,因为其内部没有生成新的对象[string appendString:@" hans"];NSLog(@"name = %@", person.name); 
     总结:用copy与strong取决于需求,如果不希望被外界更改用copy,反之用strong