在学习动态规划过程中,下面是我自己实现的LIS,时间复杂度O(n),不知道正确与否,先记下来

#include <iostream>
#include <algorithm>
#include <math.h>
using namespace std;
const int MAXN = 510;
int N;
int LF[MAXN];
int LDp[MAXN] = { 0 };

int main() {
	bool changup = false;
	int MAXNum = -1;
	int MAXIndexes = 0;
	cin >> N;
	for (int i = 0; i < N; ++i) {
		cin >> LF[i];
	}
	LDp[0] = 1;
	for (int i = 1; i < N; ++i) {
		if (LF[i] >= LF[i - 1]) {
			if (LF[i] >= MAXNum && changup == true) {  
				MAXNum = LF[i];
				LDp[i] += LDp[MAXIndexes] + 1;
				changup = false;
			}
			else {
				MAXIndexes = i;
				LDp[i] = LDp[i - 1] + 1;
			}
		}
		else {
			changup = true;
			LDp[i] = 1;
		}
	}
    //输出
	for (int i = 0; i < N; ++i) {
		cout << LDp[i] << " ";
	}
	cout << endl;
	system("PAUSE");
	return 0;
}