方法一
摘自Python查找列表中某个元素返回所有下标
方法二
name = ['hello', 'world', 'a', 'b', 'c', 1, 2, 3, 'hello', 'world', 'a', 'b', 'c', 1, 2, 3]
first_pos = 0
for i in range(name.count('a')):
new_list = name[first_pos:]
next_pos = new_list.index(2) + 1
print('find ', first_pos + new_list.index('a'))
first_pos += next_pos
# 运行结果:
# find 2
# find 10