我在这里有一个应用程序添加了数字.我这里有4个edittexts.我想要发生的是,当我在其中一个edittexts中没有输入时,它会假设我输入了0.如何才能完成?这是我的代码:
public class Order extends Activity {
Button GoBackHome;
private Button button1;
private EditText txtbox1,txtbox2,txtbox3,txtbox4;
private TextView tv;
Button PayNow;
@Override
public void onBackPressed() {
}
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.order);
GoBackHome = (Button) findViewById(R.id.gohomebutton);
PayNow = (Button) findViewById(R.id.button2);
txtbox1= (EditText) findViewById(R.id.editText1);
button1 = (Button) findViewById(R.id.button1);
tv = (TextView) findViewById(R.id.editText5);
txtbox2= (EditText) findViewById(R.id.editText2);
txtbox3= (EditText) findViewById(R.id.editText3);
txtbox4= (EditText) findViewById(R.id.editText4);
button1.setOnClickListener(new clicker());
GoBackHome.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
final Intent i = new Intent(Order.this, MainActivity.class);
startActivity(i);
}
});
PayNow.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
final Intent i = new Intent(Order.this, Payment.class);
startActivity(i);
}
});
}
class clicker implements Button.OnClickListener
{
public void onClick(View v)
{
String a,b,c,d;
Integer vis;
a = txtbox1.getText().toString();
b = txtbox2.getText().toString();
c = txtbox3.getText().toString();
d = txtbox4.getText().toString();
vis = Integer.parseInt(a)*2+Integer.parseInt(b)*3+Integer.parseInt(c)*4+Integer.parseInt(d)*5;
tv.setText(vis.toString());
}
}
}