1. Please specify what does “func()” do with the list "pParam", and what are the errors.
struct LIST
{
int nValue;
struct LIST * pPrev;
struct LIST * pNext;
};
struct LIST * func(struct LIST * pParam)
{
struct LIST* pCur = pParam;
struct LIST* pNext;
struct LIST* pPrev = NULL;
struct LIST* pTail;
struct LIST* pReturn = NULL; if (pCur == NULL)
{
return pReturn;
}
else
{
pPrev = pCur->pPrev;
if (pCur->pNext == NULL)
{
pReturn = pCur;
}
else
{
pReturn = pCur->pNext;
}
} while (pCur != NULL)
{
pNext = pCur->pNext;
if (pNext == NULL)
{
return pReturn;
}
else
{
pTail = pNext->pNext; pNext->pPrev = pPrev;
pNext->pNext = pCur;
pCur->pPrev = pNext;
if (pTail == NULL)
{
pCur->pNext = pTail;
}
else
{
if (pTail->pNext == NULL)
{
pCur->pNext = pTail;
}
else
{
pCur->pNext = pTail->pNext;
}
}
} pPrev = pCur;
pCur = pTail;
} return pReturn;
}
2. Please complete the standard C function: memmove(), here is the description (don’t use any C standard function):
void * memmove (void *to, const void *from, unsigned int size)
memmove copies the size bytes at from into the size bytes at to. The value returned by memmove is the value of to.
3. please complete this function, get binary tree’s depth. For example, the following binary tree’s depth is 4. The function returns depth.
1
/ \
2 3
/ \
4 5
/ \
6 7struct NODE
{
struct NODE* pLeft; // pLeft is NULL if it has no left sub node
struct NODE* pRight; // pRight is NULL if it has no right sub node
};
int GetDepth(const struct NODE* pRoot)
{
}4. A worker needs to do A work and B work. B’s priority is higher than A. For example, if he shall do A from 9:00 to 13:00, and shall doing B from 10:00 to 11:00, his choice shall be doing A from 9:00 to 10:00, doing B from 10:00 to 11:00, and doing A from 11:00 to 13:00.
Complete the following function (you can use pseudo-code or solution steps explanation instead of actual code), ”pSchedule“ is a worker’s work schedule (it’s an array), "nNum" is number of elements in array "pSchedule", "ppResult" is the result array which shall be returned and its buffer shall be allocated by yourself, "nRNum" is number of elements in “ppResult". The time phases in "pSchedule" cover each other, and not sorted, the output data in "ppResult" shall be a new schedule that are not covered of any phase, and sorted by start time. Return 0 if success.
enum WORK
{
A, // A work
B // B work
};
struct SCHED
{
int nStartHour; // at that hour work start
int nEndHour; // at that hour work end
enum WORK work; // work type
};
int func(const struct SCHED* pSchedule, unsigned int nNum, struct SCHED** ppResult, unsigned int& nRNum)
{
}1. 请指出以下函数对参数"pParam"做了什么动作，并指出其中的错误
将链表中的元素奇数位与偶数位互换。
int func(struct LIST * pParam)
{
// … …
while (pCur != NULL)
{
pNext = pCur->pNext;
if (pNext == NULL)
{
pCur->pPrev = pPrev;
return pReturn;
}
// … …
}
return pReturn;
}2. 请完成标准C函数：memmove()
void *memmove(void *dest, const void *src, size_t count)
{
char *tmp;
const char *s; if (dest == NULL || src == NULL)
{
return NULL;
} if (dest <= src) {
tmp = dest;
s = src;
while (count–)
*tmp++ = *s++;
} else {
tmp = dest;
tmp += count;
s = src;
s += count;
while (count–)
*–tmp = *–s;
}
return dest;
}3. 请完成以下函数，返回二叉树的深度。例如下面所示二叉树的深度为4。
#include <stdlib.h>
struct NODE
{
struct NODE* pLeft; // pLeft is NULL if it has no left sub node
struct NODE* pRight; // pRight is NULL if it has no right sub node
};int GetDepth(const struct NODE* pRoot)
{
if (pRoot == NULL)
{
return 0;
}
int nLeft = GetDepth(pRoot->pLeft);
int nRight = GetDepth(pRoot->pRight);
return nLeft > nRight ? nLeft + 1 : nRight + 1;
}4. 工人需要做A工作和B工作。B工作的优先级比A工作更高。例如，如果他要在9:00至13:00做A工作，而且在10:00至11:00做B工作，那么他应该在9:00至10:00做A工作，在10:00至11:00做B工作，在11:00至13:00做A工作。
完成下面函数，"pSchedule"是工人的工作计划（它是一个数组），"nNum"是数组"pSchedule"中的元素数量，"ppResult"是需要返回的结果数组，"nRNum"是结果中的元素数量。"pSchedule"中的时间段互相覆盖，而且未排序，输出结果"ppResult"中的时间段不允许有覆盖，并且按开始时间排序。函数执行成功返回０。
//以下是2011年的笔试题
5、已知2010年的1月1日是星期五，写一个函数，输入M年和N 月，计算出该月的第3个星期五是几号？
6、写SQL 语句的题，其中有一个是如何创建索引？
语法：
CREATE [索引类型] INDEX 索引名称
ON 表名(列名)
WITH FILLFACTOR = 填充因子值0~100
GO
/*实例*/
USE 库名
GO
IF EXISTS (SELECT * FROM SYSINDEXES WHERE NAME='IX_TEST_TNAME')--检测是否已经存在IX_TEST_TNAME索引
DROP INDEX TEST.IX_TEST_TNAME--如果存在则删除
--创建索引
CREATE NONCLUSTERED INDEX IX_TEST_TNAME --创建一个非聚集索引
ON TEST(TNAME) --为TEST表的TNAME字段创建索引
WITH FILLFACTOR = 30 --填充因子为30%
GO
--指定按‘IX_TEST_TNAME’索引查询
总结：
数据库中的索引是某个表中一列或多列值的集合和相应的指向表中物理标识这些值的数据页的逻辑指针清单。
2.分类：
唯一索引(UNIQUE)：不允许两行具有相同的索引值（创建了唯一约束，系统将自动创建唯一索引）
主键索引：主键索引要求主键中的每个值是唯一的，（创建主键自动创建主键索引）
聚集索引(CLUSTERED)：表中各行的物理顺序与键值的逻辑（索引）顺序相同，表中只能包含一个聚集索引，主键列默认为聚集索引
非聚集索引(NONCLUSTERED)：表中各行的物理顺序与键值的逻辑（索引）顺序不匹配，表中可以有249个非聚集索引
3.创建索引的标准：用于频繁搜索的列；用于对数据进行排序的列
注意：如果表中仅有几行，或列中只包含几个不同的值，不推荐创建索引，因为SQL Server 在小型表中用索引搜索数据所花的时间比逐行搜索更长。
