java判断两个时间相等 java 时间判断

SimpleDateFormat formatter = new SimpleDateFormat("HH:mm:ss");
  
  //时分秒
  Calendar cal = Calendar.getInstance();
  int hour = cal.get(Calendar.HOUR_OF_DAY);
  int minute = cal.get(Calendar.MINUTE);
  int second = cal.get(Calendar.SECOND);

  String sBuffer = hour + ":" + minute + ":" + second;
  
  Date dt1 = formatter.parse("00:00:00");//将字符串转换为date类型
  Date dt2 = formatter.parse("07:00:00");//将字符串转换为date类型
  Date dt3 = formatter.parse("24:00:00");
  
  // 系统当前时分秒
  Date dt4 = formatter.parse(sBuffer);
  if(dt1.getTime() < dt4.getTime() && dt4.getTime() < dt2.getTime()) {
   System.out.println("0～7点：来早了～");
  }
  
  if(dt2.getTime() < dt4.getTime() && dt4.getTime() < dt3.getTime()) {//比较时间大小,如果dt1大于dt2
   System.out.println("10～24点：来晚了～");
  }

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