数组中数字出现的次数 II
在一个数组 nums 中除一个数字只出现一次之外,其他数字都出现了三次。请找出那个只出现一次的数字。
示例 1:
输入:nums = [3,4,3,3]
输出:4
示例 2:
输入:nums = [9,1,7,9,7,9,7]
输出:1
#方法一
from collections import Counter
def numscounter(varlist):
newdict = Counter(varlist)
for k,v in newdict.items():
if v == 1:
return k
print(numscounter([3,4,3,3]))
print(numscounter([9,1,7,9,7,9,7]))
# 方法二
def list_numsidentical(list_nums):
for i in range(0, len(list_nums)):
a = list_nums[0]
del list_nums[0]
if a in list_nums:
continue
else:
return a
print(list_numsidentical([3, 4, 3, 3]))
print(list_numsidentical([9, 1, 7, 9, 7, 9, 7]))
# 方法三
def list_countone(list_nums):
for i in list_nums:
if list_nums.count(i) == 1:
list_num = i
return list_num
print(list_countone([3, 4, 3, 3]))
print(list_countone([9, 1, 7, 9, 7, 9, 7]))
# 方法四
def list_onelambda(list_nums):
n = min(list_nums, key=lambda v: list_nums.count(v))
return n
print(list_onelambda([3, 4, 3, 3]))
print(list_onelambda([9, 1, 7, 9, 7, 9, 7]))