C++ char强行转换成指针

#include <iostream>
 
 

  #include <string>
 
 

  using namespace std;
 
 

  
 

  int main()
 
 

  {
 
 
 int a=12;
 
 
 cout<<a<<endl;
 
 
 cout<<&a<<endl;
 
 
 char addr[20]="0012FF44";
 
 

  
 
 cout<<"强制地址转换后："<<endl;
 
 
 int *p=(int *)addr;
 
 
 p=p+5;
 
 
 cout<<p<<endl;
 
 
 cout<<*p<<endl;
 
 
 return 0;
 
 

  }