SqlServer 获取工作日(周六、周日休息，周六日不休息，周六不休息)

-- =============================================
-- Author:    LJB
-- Create date:2019年3月19日14:29:23
-- Description:    获取工作日
-- =============================================
CREATE FUNCTION [dbo].[f_GetWorkday](@bdate DATETIME, @edate DATETIME,@workDayEnum INT)
RETURNS INT
AS 
  BEGIN
    DECLARE @workdays INT;
    DECLARE @saturdayCount INT;
    IF(@edate <= CONVERT(datetime,'1900-01-01'))
        SET @edate = GETDATE();
    
    IF(@workDayEnum = 1) --周六、周日休息
    BEGIN
        SET @workdays = 0;
    END
    ELSE IF(@workDayEnum = 2) --周六、周日不休息
    BEGIN
        SET @workdays  = DATEDIFF(day,@bdate,@edate) + 1;
        RETURN @workdays;
    END
    ELSE --周六不休息
    BEGIN 
        SET @workdays = datediff(wk,@bdate,@edate);--两个时间内有多少个周六
    END
    --一周5个工作日计算
    while DATEDIFF(d, @bdate, @edate) >= 0     
    begin                         
        if datepart(dw,@bdate) > 1 and datepart(dw,@bdate) < 7      
        begin
            select @workdays=@workdays+1      
        end     
        select @bdate=dateadd(day,1,@bdate)       
    end   
    RETURN @workdays;
  END
GO