​​点击打开链接​​

A + B Problem II

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 413635    Accepted Submission(s): 80168


Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

 


Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

 


Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

 


Sample Input 

2 1 2 112233445566778899 998877665544332211

 


Sample Output 

Case 1: 1 + 2 = 3 Case 2: 112233445566778899 + 998877665544332211 = 1111111111111111110

 


刷ACM的题，大数用C语言写，只能用数组模拟，很麻烦，现在大二了，学习了java，今天做的第一个大数加法题，绝对比C语言要简单的多了。

import java.math.*;
import java.util.*;
import java.*;
public class Main{
    public static void main(String[] args){
        Scanner scanner = new Scanner(System.in);
        int n;
        n = scanner.nextInt();
        for (int i=1;i<=n;i++){
            System.out.println("Case " + i + ":");  
            BigInteger a,b,c;
            a = scanner.nextBigInteger();
            b = scanner.nextBigInteger();
            c = a.add(b);
            System.out.println(a.toString() + " + " + b.toString() + " = " + c.toString());
            if(i!=n){
                System.out.println();
            }
        }
    }
}