Suppose you have a long flowerbed in which some of the plots are planted and some are not. However, flowers cannot be planted in adjacent plots - they would compete for water and both would die.

Given a flowerbed (represented as an array containing 0 and 1, where 0 means empty and 1 means not empty), and a number n, return if n new flowers can be planted in it without violating the no-adjacent-flowers rule.

Example 1:

Input: flowerbed = [1,0,0,0,1], n = 1 Output: True

Example 2:

Input: flowerbed = [1,0,0,0,1], n = 2 Output: False

Note:
The input array won’t violate no-adjacent-flowers rule.
The input array size is in the range of [1, 20000].
n is a non-negative integer which won’t exceed the input array size.

思路：
【统计连续空地】使用count来进行统计。
【统计连续空地上可种】(count -1) / 2
【特殊处理 + 最后一个count】 count / 2 

class Solution
    public boolean canPlaceFlowers(int[] flowerbed, int n) {
        int count = 1;
        int result = 0;
        for(int i=0; i<flowerbed.length; i++) {
            if(flowerbed[i] == 0) {
                count++;
            }else {
                result += (count-1)/2;
                count = 0;
            }
        }
        if(count != 0) result += count/2;
        return