Codeforces Round #398 (Div. 2) 题解(待续)

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A Codeforces Round #398 (Div. 2)

#include<bits/stdc++.h>
using namespace std;
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
                        For(j,m-1) cout<<a[i][j]<<' ';\
                        cout<<a[i][m]<<endl; \
                        } 
#pragma
#define
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
ll mul(ll a,ll b){return (a*b)%F;}
ll add(ll a,ll b){return (a+b)%F;}
ll sub(ll a,ll b){return ((a-b)%F+F)%F;}
void upd(ll &a,ll b){a=(a%F+b%F)%F;}
int read()
{
    int x=0,f=1; char ch=getchar();
    while(!isdigit(ch)) {if (ch=='-') f=-1; ch=getchar();}
    while(isdigit(ch)) { x=x*10+ch-'0'; ch=getchar();}
    return x*f;
} 
#define
int a[MAXN];
int c[MAXN];
priority_queue<int> q;
int main()
{
//  freopen("A.in","r",stdin);
//  freopen(".out","w",stdout);
    int n=read();
    For(i,n) cin>>a[i],c[i]=a[i];
    sort(c+1,c+1+n);
    int p=n;    
    For(i,n) {
        q.push(a[i]);
        bool fl=0;
        while(!q.empty()&&q.top()==c[p]) {
            if (!fl) fl=1;else putchar(' ');
            cout<<c[p--];
            q.pop();
        }
        puts("");
    }                          
    return 0;
}

B The Queue

还有点小问题

C Garland

#include<bits/stdc++.h>
using namespace std;
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
                        For(j,m-1) cout<<a[i][j]<<' ';\
                        cout<<a[i][m]<<endl; \
                        } 
#pragma
#define
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
ll mul(ll a,ll b){return (a*b)%F;}
ll add(ll a,ll b){return (a+b)%F;}
ll sub(ll a,ll b){return ((a-b)%F+F)%F;}
void upd(ll &a,ll b){a=(a%F+b%F)%F;}
int read()
{
    int x=0,f=1; char ch=getchar();
    while(!isdigit(ch)) {if (ch=='-') f=-1; ch=getchar();}
    while(isdigit(ch)) { x=x*10+ch-'0'; ch=getchar();}
    return x*f;
} 
#define
vi edges[MAXN];
int fa[MAXN],d[MAXN];
int n,c[MAXN]={0},a[MAXN]={0},b[MAXN]={0};
void dfs(int x,int dep=0) {
    Rep(i,SI(edges[x])) {
        int v=edges[x][i];
        if (b[v]) continue;
        dfs(v,dep+1);
        a[x]+=a[v];
    }
    a[x]+=c[x];
    d[x]=dep;
}
void dfs2(int x) {
    Rep(i,SI(edges[x])) {
        int v=edges[x][i];
        dfs2(v);
        b[v]=1;
    }
    b[x]=1;
}

int main()
{
//  freopen("C.in","r",stdin);
//  freopen(".out","w",stdout);
    cin>>n;
    int tt=0,ro;
    For(i,n) {
        fa[i]=read();
        if (!fa[i]) ro=i;
        int t=read();
        edges[fa[i]].pb(i);
        c[i]=t;tt+=t;
    }
    if (tt%3!=0) {
        puts("-1");return 0;
    }
    tt/=3;
    MEM(a)
    dfs(ro);
    int ans1=0,dp=-1;
    For(i,n) if (a[i]==tt&&i!=ro && dp<=d[i]) ans1=i,dp=d[i];
    if (!ans1)   {
        puts("-1");return 0;
    }
    dfs2(ans1);
    MEM(a) b[ans1]=1;
    dfs(ro);
    int ans2=0; dp=-1;
    For(i,n) if (!b[i] && a[i]==tt&&i!=ro && dp<=d[i]) ans2=i,dp=d[i];
    if (!ans2)   {
        puts("-1");return 0;
    }
    if (ans1>ans2) swap(ans1,ans2);
    cout<<ans1<<' '<<ans2<<endl;

    return 0;
}

D Cartons of milk

二分

#include<bits/stdc++.h>
using namespace std;
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
#define
                        For(j,m-1) cout<<a[i][j]<<' ';\
                        cout<<a[i][m]<<endl; \
                        } 
#pragma
#define
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
ll mul(ll a,ll b){return (a*b)%F;}
ll add(ll a,ll b){return (a+b)%F;}
ll sub(ll a,ll b){return ((a-b)%F+F)%F;}
void upd(ll &a,ll b){a=(a%F+b%F)%F;}
int read()
{
    int x=0,f=1; char ch=getchar();
    while(!isdigit(ch)) {if (ch=='-') f=-1; ch=getchar();}
    while(isdigit(ch)) { x=x*10+ch-'0'; ch=getchar();}
    return x*f;
} 
#define
ll a[MAXN];
pair<ll,int > b[MAXN];
ll c[MAXN];
int n,m,k;
ll calc(int p) {
    int l1=1,l2=m-p+1;
    int t=0;
    For(i,n+p) {
        if (l1>n) c[++t]=b[l2].fi,l2++;
        else if (l2>m) c[++t]=a[l1],l1++;
        else {
            if (a[l1]<b[l2].fi) c[++t]=a[l1],l1++;
            else c[++t]=b[l2].fi,l2++;
        }       
    }
    sort(c+1,c+1+t);
    ll dt=0,nd=k;
    For(i,t) {
        if (!nd) ++dt,nd+=k;
        if (c[i]<dt) return 0;
        nd--;
    }
    return 1;
}
int main()
{
//  freopen("D.in","r",stdin);
//  freopen(".out","w",stdout);
    n=read(),m=read(),k=read();
    For(i,n) a[i]=read();
    For(i,m) b[i]=mp(read(),i);
    sort(a+1,a+1+n);
    sort(b+1,b+1+m);
    int l=0,r=m,ans=0;
    if (!calc(0)) puts("-1");
    else {
        while(l<=r) {
            int m=(l+r)/2;
            if (calc(m)) ans=m,l=m+1;
            else r=m-1;
        }
        cout<<ans<<endl;
        bool fl=0;
        Fork(i,m-ans+1,m) {
            if (!fl) fl=1;
            else putchar(' ');
            cout<<b[i].se;
        }puts("");
    }



    return 0;
}