SQL刷题之单表查询
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文章目录
基础练习
查询所有列

sql:
select
*
from
user_profile;
查询多列

sql:
select
device_id,
gender,
age,
查询结果去重

sql:
select
distinct university
from
user_profile
方法二:
SELECT university
FROM user_profile
GROUP BY university
查询结果限制返回行数

sql:
select
device_id
from
user_profile
limit
2
将查询后的列重新命名

sql:
select
device_id as 'user_infos_example'
from
user_profile
where
id between 1 and 2
查找学校是北大的学生信息

sql:
select
device_id,
university
from
user_profile
where
university = '北京大学'
方法二:
select
device_id,
university
from
user_profile
where
university = '北京大学'
and device_id = user_profile.device_id;
查找后排序

sql:
查找后多列排序

sql:
select
device_id,
gpa,
age
from
user_profile
order by
gpa,
查找后降序排列

sql:
select
device_id,
gpa,
age
from
user_profile
order by
gpa desc,
查找年龄大于24岁的用户信息

sql:
select
device_id,
gender,
age,
university
from
user_profile
where
age > 24
查找某个年龄段的用户信息

sql:
select
device_id,
gender,
age
from
user_profile
where
age between 20 and 23
查找除复旦大学的用户信息

sql:
select
device_id,
gender,
age,
university
from
user_profile
where
university not in ('复旦大学')
或者:
select
device_id,
gender,
age,
university
from
user_profile
where
university != ('复旦大学')
用where过滤空值练习

sql:
select
device_id,
gender,
age,
university
from
user_profile
where
age is NOT NULL
高级操作符练习(1)

sql:
select
device_id,
gender,
age,
university,
gpa
from
user_profile
where
gpa > 3.5
and gender = 'male'
高级操作符练习(2)

sql:
select
device_id,
gender,
age,
university,
gpa
from
user_profile
where
university = '北京大学'
or gpa > 3.7
Where in 和Not in

sql:
select
device_id,
gender,
age,
university,
gpa
from
user_profile
where
university in ('北京大学', '复旦大学', '山东大学')
操作符混合运用

sql:
select
device_id,
gender,
age,
university,
gpa
from
user_profile
where
gpa > 3.5
and university = '山东大学'
or gpa > 3.8
and university = '复旦大学'
查看学校名称中含北京的用户

sql:
select
device_id,
age,
university
from
user_profile
where
university like '北京%'
高级查询
查找GPA最高值

sql:
select
gpa
from
user_profile
where
university = '复旦大学'
order by
gpa desc # 降序
limit
1
或者:
select
max(gpa)
from
user_profile
where
university = '复旦大学'
计算男生人数以及平均GPA

sql:
select
count(gender) as male_num,
avg(gpa) as avg_gpa
from
user_profile
where
gender = 'male'
分组计算练习题


sql:
select
gender,
university,
count(device_id) as user_num,
avg(active_days_within_30) as avg_active_days,
avg(question_cnt) as avg_question_cnt
from
user_profile
group by
gender,
分组过滤练习题
题目:现在运营想查看每个学校用户的平均发贴和回帖情况,寻找低活跃度学校进行重点运营,请取出平均发贴数低于5的学校或平均回帖数小于20的学校。
sql:
#聚合函数结果作为筛选条件时,不能用where,而是用having语法,配合重命名即可;
select
university,
avg(question_cnt) as avg_question_cnt,
avg(answer_cnt) as avg_answer_cnt
from user_profile
group by university
having avg_question_cnt<5 or avg_answer_cnt<20
分组排序练习题



sql:
select
university,
avg(question_cnt)
恭喜
单表查询你已经基本的知识会了,恭喜入门!本篇题目都很简单,如果平均每个题你能在一分钟内完成就算基本掌握了。