蓝桥杯第九届蓝桥杯Java语言C组

原创

✿ฺ_Value_✿ฺ 2021-12-30 15:03:23 博主文章分类：动态规划 ©著作权

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题目标签

1	2	3	4	5
哪天返回	猴子分香蕉	字母阵列	第几个幸运数	书号验证
6	7	8	9	10
打印大X	缩位求和	等腰三角形	小朋友崇拜圈	耐摔指数

1.哪天返回

蓝桥杯第九届蓝桥杯Java语言C组_vim

package 哪天返回;

public class Main {
	public static void main(String[] args) {
		int money = 1;
		int sum = 0;
		for (int i = 1;  ; i++,money+=2) {
			sum+=money;
			System.err.println("第"+i+"天 ："+sum);
			if (sum >= 108) {
				break;
			}
		}
	}
	}

2.猴子分香蕉

蓝桥杯第九届蓝桥杯Java语言C组_i++_02

package 猴子分香蕉;
public class Main {
	public static void main(String[] args) {
		for (int i = 17; i < 1000000; i++) {
			int num = i;
			if (num % 5 == 1) {
				num=num-1;
				num -= (num/5);
				if (num%5==2) {
					num -= 2;
					num -= (num/5);
					if (num%5==3) {
						num-=3;
						num -=(num/5);
						if (num%5==4) {
							num-=4;
							num-=(num/5);
							if (num%5==0) {
								System.out.println(i);
								return;
							}
						}
					}
				}
			}
		}
	}
	}

3.字母阵列

蓝桥杯第九届蓝桥杯Java语言C组_java_03

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package 字母阵列;

import java.util.Scanner;

public class Main {
	static int count = 0;
public static void main(String[] args) {
	Scanner sr  = new Scanner(System.in);
	//创建地图
	char[][] map = new char[100][100];
	for (int i = 0; i < map.length; i++) {
		String s = sr.next();
		map[i] = s.toCharArray();
	}
	//寻找L起点
	for (int i = 0; i < map.length; i++) {
		for (int j = 0; j < map[0].length; j++) {
			dfs(i, j, map);//以此位置为起点
		}
	}
	System.out.println(count);
}

private static void dfs(int i, int j, char[][] map) {
	//LANQIAO
	String Model = "LANQIAO";
	//方向移动数组
	int[] dx = {1,-1,0,0,-1,-1,1,1};
	int[] dy = {0,0,-1,1,-1,1,-1,1};
	for (int k = 0; k < 8; k++) {
		int nx = i;//起点位置
		int ny = j;
		int step = 0;//字符匹配计数器
		//按此方向循环蓝桥长度
		for (int p = 0; p < Model.length(); p++) {
			nx += dx[k];
			ny += dy[k];
			if (nx >= 0 && ny >= 0 && nx < map.length && ny < map[0].length && map[nx][ny] == Model.charAt(p)) {
				step++;
				continue;
			}else {
				break;
			}
		}//此方向完美匹配长度,count++;
		if (step == Model.length()) count++;
	}
	
	return;
}
}

4.第几个幸运数

蓝桥杯第九届蓝桥杯Java语言C组_java_04

1905

package 第几个幸运数;

public class Main {
	public static void main(String[] args) {
		// 统计最后的幸运数
		int count = 0;
		// 数字太大所以用Long型，数字最后+L表示形式！！因为JAVA默认int类型~
		Long num = 59084709587505L;
		for (int i = 0; Math.pow(3, i) < num; i++) {         // 3的i次方<num
			for (int j = 0; Math.pow(5, j) < num; j++) {     // 5的j次方<num
				for (int k = 0; Math.pow(7, k) < num; k++) { // 7的k次方<num
					if (Math.pow(3, i) * Math.pow(5, j) * Math.pow(7, k) <= num) { // 如果三个次方同时相乘<num，继续循环！！
						count++; // 求得幸运数结果
					}
				}
			}
		}
		// 千万注意，因为i，j，k的for初始值为0，0没有意义，所以在原结果-1，求得答案1905！！
		System.out.println(count - 1);
	}
}

5.书号验证

蓝桥杯第九届蓝桥杯Java语言C组_算法_05

package 书号验证;

public class Main
{
	static boolean f(String s){
		int k=1;
		int sum = 0;
		for(int i=0; i<s.length(); i++){
			char c = s.charAt(i);
			if(c=='-' || c==' ') continue;
			sum += (c-'0')*(k%2==0?3:1);  //填空
			k++;
			if(k>12) break; 
		}
		
		return s.charAt(s.length()-1)-'0' == (10-sum % 10)%10;
	}
	
	public static void main(String[] args){
		System.out.println(f("978-7-301-04815-3"));
		System.out.println(f("978-7-115-38821-6"));
	}
}

6.打印大X

蓝桥杯第九届蓝桥杯Java语言C组_编程题_06 蓝桥杯第九届蓝桥杯Java语言C组_i++_07 蓝桥杯第九届蓝桥杯Java语言C组_vim_08

package 打印大X;


public class Main
{
	static void f(int h, int w){
		System.out.println(String.format("高度=%d, 笔宽=%d",h,w));
		int a1 = 0;
		int a2 = h - 1;
		
		for(int k=0; k<h; k++){
			int p = Math.min(a1,a2);
			int q = Math.max(a1+w,a2+w);
			
			for(int i=0; i<p; i++) System.out.print(" ");
			
			if(q-p<w*2){
				for(int i = p ; i < q ;i++)System.out.print("*"); ; //填空
			}
			else{
				for(int i=0; i<w; i++) System.out.print("*");
				for(int i=0; i<q-p-w*2; i++) System.out.print(" ");
				for(int i=0; i<w; i++) System.out.print("*");
			}
			System.out.println();
			a1++;
			a2--;
		}
	}
	
	public static void main(String[] args){
		f(15,3);
		f(8,5);
	}
}

7.缩位求和

蓝桥杯第九届蓝桥杯Java语言C组_算法_09

package 缩位求和;

import java.util.Scanner;

public class Main {
public static void main(String[] args) {
	Scanner sr  = new Scanner(System.in);
	String s = sr.next();
	
	while (s.length() > 1) {
		int num = 0;
		for (int i = 0; i < s.length(); i++) {
			num += s.charAt(i)-'0';
		}
		s = num+"";
	}
	System.out.println(s);
}
}

8.等腰三角形

蓝桥杯第九届蓝桥杯Java语言C组_vim_10

例如：
输入：
5

程序应该输出：
....1
...2.1
..3...2
.4.....1
567891011

再例如：
输入：
10

程序应该输出：
.........1
........2.2
.......3...2
......4.....2
.....5.......1
....6.........2
...7...........0
..8.............2
.9...............9
1011121314151617181

再例如：
输入：
15

程序应该输出：

..............1
.............2.3
............3...2
...........4.....3
..........5.......1
.........6.........3
........7...........0
.......8.............3
......9...............9
.....1.................2
....0...................8
...1.....................2
..1.......................7
.1.........................2
21314151617181920212223242526


资源约定：
峰值内存消耗（含虚拟机） < 256M
CPU消耗  < 1000ms

package 数字三角形;

import java.util.Scanner;

public class Main {
public static void main(String[] args) {
	Scanner sr = new Scanner(System.in);
	int n =sr.nextInt();
	String str = "";
	for (int i = 1; i <= n*2+3; i++) {
		str += i;
	}
	//计算整个字串长度
	int len = ( n-1 ) + ( n*2-1 ) + ( n-2 );
	str = str.substring(0,len);
	String left = str.substring(0,(n-1));
	String down = str.substring((n-1) ,(n-1) + (n*2-1));
	String right = str.substring((n-1) + (n*2-1) , len);
	right = new StringBuilder(right).reverse().toString();
//	System.out.println(left);
//	System.out.println(down);
//	System.out.println(right);
	//行
	for (int j = n-1; j >= 1; j--)
		System.out.print(".");
	System.out.println(left.charAt(0));
	
	for (int i = 2; i < n; i++) {
		//输出前置*
		for (int j = n-i; j >= 1; j--)
			System.out.print(".");
		//左
		System.out.print(left.charAt(i-1));
		//输出中间*
		for (int j = 1; j <= i-2; j++)
			System.out.print("..");
		System.out.print(".");
		//右
		System.out.println(right.charAt(i-2));
	}
	System.out.println(down);
}
}

9.小朋友崇拜圈

蓝桥杯第九届蓝桥杯Java语言C组_编程题_11

蓝桥杯第九届蓝桥杯Java语言C组_java_12

package 小朋友崇拜圈;

import java.util.ArrayList;
import java.util.Scanner;

public class Main {
public static void main(String[] args) {
	Scanner sr = new Scanner(System.in);
	int n = sr.nextInt();
	int max = 0;//最大值圈
	int[] child = new int[n+1];//存储小朋友崇拜的人,序号1开始,所以+1
	for (int i = 1; i < child.length; i++) {
		child[i] = sr.nextInt();
	}
	//遍历起点
	for (int i = 1; i < child.length; i++) {
		//从这个起点开始寻找崇拜圈
		ArrayList<Integer> list = new ArrayList<Integer>();
		list.add(i);
		while (!list.isEmpty()) {
			//看看刚加进来的小朋友崇拜谁
			int id = child[list.get(list.size()-1)];
			//这个人之前被崇拜你的人崇拜过,形成圈
			if (list.contains(id)) {
				System.out.print(list+"   ");
				System.out.println(list.size() - list.indexOf(id));
				max = Math.max(max, list.size() - list.indexOf(id));
				break;
			}//寻找新加进来的整个人崇拜的人
			list.add(id);
		}
	}
	System.out.println(max );
}
}

10.耐摔指数

蓝桥杯第九届蓝桥杯Java语言C组_i++_13

package 耐摔次数;

public class Main {
	
	public static void main(String[] args) {
	
		int[][] dp = new int[1000+1][3+1];
		//手机数量为1时的测试次数了
		for (int i = 1; i < dp.length; i++) {
			dp[i][1] = i;
		}
		for (int i = 1; i < dp.length; i++) {
			//由于上面已经设置了手机数量为1时的测试次数了
			//所以只需从手机数量为2开始进行遍历即可
			for (int j = 2; j < dp[0].length; j++) {
				//取一个不影响结果的数
				int min = Integer.MAX_VALUE;
				//从第1层到第 i 层,逐一尝试所有决策,取最优的
				//每一层最坏情况下(max 测试次数最多)的最好结果(min)
				for (int k = 1; k <= i; k++) {
					min = Math.min(min, 
							Math.max(dp[k-1][j-1], dp[i-k][j]));
				}
				//需要加上本次测试的次数,因此需要+1
				dp[i][j]=min+1;
			}
		}
		System.out.println(dp[1000][3]);
	}
}