LeetCode题解(0158)：用Read4读取N个字符II(Python)

题目：​​原题链接​​（困难）

标签：字符串

解法	时间复杂度	空间复杂度	执行用时
Ans 1 (Python)	O ( N )	O ( 1 )	40ms (74.71%)
Ans 2 (Python)
Ans 3 (Python)

解法一：

class Solution:
    def __init__(self):
        self.cache = []
        self.size = 0
        self.finish = False

    def read(self, buf: List[str], n: int) -> int:
        while not self.finish and self.size < n:
            self.read4()

        length = min(self.size, n)
        self.size -= length
        buf[:length] = self.cache[:length]
        self.cache[:length] = []

        return length

    def read4(self):
        temp = [" "] * 4
        size = read4(temp)
        for i in range(size):
            self.cache.append(temp[i])
            self.size += 1
        if size < 4:
            self.finish = True