题目:原题链接(简单)
标签:字符串、哈希表
解法 | 时间复杂度 | 空间复杂度 | 执行用时 |
Ans 1 (Python) | O ( N + B ) O(N+B) O(N+B) : N为句子长度、B为禁用列表长度 | O ( N + B ) O(N+B) O(N+B) | 40ms (92.22%) |
Ans 2 (Python) | |||
Ans 3 (Python) |
解法一(哈希表):
def mostCommonWord(self, paragraph: str, banned: List[str]) -> str:
hashmap = {}
for word in re.split("[ ,.?!]", paragraph.lower()):
word = "".join(list(filter(str.isalpha, word)))
if len(word) > 0:
if word not in hashmap:
hashmap[word] = 1
else:
hashmap[word] += 1
times = 0
ans = ""
for key, value in hashmap.items():
if value > times and key not in banned:
ans = key
times = value
return ans