题目:​​原题链接​(简单)

标签:字符串、哈希表

解法

时间复杂度

空间复杂度

执行用时

Ans 1 (Python)

O ( N + B ) O(N+B) O(N+B) : N为句子长度、B为禁用列表长度

O ( N + B ) O(N+B) O(N+B)

40ms (92.22%)

Ans 2 (Python)

Ans 3 (Python)

解法一(哈希表):

def mostCommonWord(self, paragraph: str, banned: List[str]) -> str:
hashmap = {}
for word in re.split("[ ,.?!]", paragraph.lower()):
word = "".join(list(filter(str.isalpha, word)))
if len(word) > 0:
if word not in hashmap:
hashmap[word] = 1
else:
hashmap[word] += 1

times = 0
ans = ""
for key, value in hashmap.items():
if value > times and key not in banned:
ans = key
times = value
return ans