题目:原题链接(中等)
标签:字符串
解法 | 时间复杂度 | 空间复杂度 | 执行用时 |
---|---|---|---|
Ans 1 (Python) | O ( N ) O(N) O(N) | O ( N ) O(N) O(N) | 44ms (28.41%) |
Ans 2 (Python) | |||
Ans 3 (Python) |
解法一:
class Solution:
def areSentencesSimilar(self, sentence1: str, sentence2: str) -> bool:
sentence1, sentence2 = sentence1.split(" "), sentence2.split(" ")
size1, size2 = len(sentence1), len(sentence2)
i, j = 0, 0
while i < size1 and i < size2:
if sentence1[i] == sentence2[i]:
i += 1
else:
break
while j < size1 - i and j < size2 - i:
if sentence1[size1 - j - 1] == sentence2[size2 - j - 1]:
j += 1
else:
break
return i + j == min(size1, size2) or (i == size1 == size2 and j == 0)