题目:原题链接(中等)

标签:字符串

解法 时间复杂度 空间复杂度 执行用时
Ans 1 (Python) O ( N ) O(N) O(N) O ( N ) O(N) O(N) 44ms (28.41%)
Ans 2 (Python)
Ans 3 (Python)

解法一:

class Solution:
    def areSentencesSimilar(self, sentence1: str, sentence2: str) -> bool:
        sentence1, sentence2 = sentence1.split(" "), sentence2.split(" ")
        size1, size2 = len(sentence1), len(sentence2)

        i, j = 0, 0

        while i < size1 and i < size2:
            if sentence1[i] == sentence2[i]:
                i += 1
            else:
                break

        while j < size1 - i and j < size2 - i:
            if sentence1[size1 - j - 1] == sentence2[size2 - j - 1]:
                j += 1
            else:
                break

        return i + j == min(size1, size2) or (i == size1 == size2 and j == 0)