The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N

A P L S I I G

Y   I   R

And then read line by line: "PAHNAPLSIIGYIR"

Write the code that will take a string and make this conversion given a number of rows:

string convert(string s, int numRows);

Example 1:

Input: s = "PAYPALISHIRING", numRows = 3

Output: "PAHNAPLSIIGYIR"

Example 2:

Input: s = "PAYPALISHIRING", numRows = 4

Output: "PINALSIGYAHRPI"

Explanation:

P     I    N

A   L S  I G

Y A   H R

P     I

来源:力扣(LeetCode)

链接:https://leetcode-cn.com/problems/zigzag-conversion

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【LeetCode】6. ZigZag Conversion_商业

题解讲的真好

class Solution {
public:
string convert(string s, int numRows) {
string ret;
int n = s.size();
int times = 2*numRows-2;
if(n<=1) return s;
if(numRows == 1)return s;
int i = 0;
while(times*i<n)
{
ret += s[times*i];
i++;
}
for(int j = 1; j<numRows-1; j++)
{
ret += s[j];
for(int i = 1; ;i++)
{
if(times*i-j<n) ret += s[times*i-j];
if(times*i+j<n) ret += s[times*i+j];
else break;
}
}
i = 0;
while((times*i + numRows-1)<n)
ret += s[times*i++ + numRows-1];
return ret;
}
};

【LeetCode】6. ZigZag Conversion_商业_02

我画了一个特别丑的图就出来了

Z型排序可以由第一种演变过去。。。Z型还可以变成后面那种,就可以按照代码的思路去写了。。