Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 11042 | Accepted: 5100 |
Description
possible to reach through lines every other place, however it need not be a direct connection, it can go through several exchanges. From time to time the power supply fails at a place and then the exchange does not operate. The officials from TLC realized that in such a case it can happen that besides the fact that the place with the failure is unreachable, this can also cause that some other places cannot connect to each other. In such a case we will say the place (where the failure
occured) is critical. Now the officials are trying to write a program for finding the number of all such critical places. Help them.
Input
by one space. Each block ends with a line containing just 0. The last block has only one line with N = 0;
Output
Sample Input
5 5 1 2 3 4 0 6 2 1 3 5 4 6 2 0 0
Sample Output
1 2
Hint
#include<stdio.h> #include<string.h> #include<stack> #include<algorithm> #define MAX 1100 #define MAXM 2000100 #define INF 0x7fffff using namespace std; struct node { int beg,end,next; }edge[MAXM]; int low[MAX],dfn[MAX]; int head[MAX],ans; int dfsclock; int iscut[MAX]; void init() { ans=0; memset(head,-1,sizeof(head)); } void add(int u,int v) { edge[ans].beg=u; edge[ans].end=v; edge[ans].next=head[u]; head[u]=ans++; } void tarjan(int u,int fa) { int v,i; low[u]=dfn[u]=++dfsclock; int son=0; for(i=head[u];i!=-1;i=edge[i].next) { v=edge[i].end; if(!dfn[v]) { son++; tarjan(v,u); low[u]=min(low[u],low[v]); if(u!=fa&&dfn[u]<=low[v]) iscut[u]=1; } else low[u]=min(dfn[v],low[u]); } if(fa==u&&son>1) iscut[u]=1; } void find(int l,int r) { memset(low,0,sizeof(low)); memset(dfn,0,sizeof(dfn)); memset(iscut,0,sizeof(iscut)); dfsclock=0; for(int i=l;i<=r;i++) { if(!dfn[i]) tarjan(i,i); } } int main() { int n,m,j,i,t; int a,c,len; char b; char s[5010]; while(scanf("%d",&n),n) { init(); int sum=0; while(scanf("%d", &a), a) { while(getchar() != '\n') { scanf("%d", &c); add(a,c); add(c,a); } } // while(scanf("%d",&a),a) 我真的搞不懂我这个输入错在哪里一直wa // { // while(scanf("%c",&b)&&b!='\n') // { // c=b-'0'; // add(a,c); // add(c,a); // } // } find(1,n); for(i=1;i<=n;i++) { if(iscut[i]) sum++; } printf("%d\n",sum); } return 0; }