2019独角兽企业重金招聘Python工程师标准>>> 
1.使用线程池ExecutorService exec = Executors.newFixedThreadPool(1)；
2.根据线程返回的结果Future，进行相应处理
demo如下：
、
package com.test;
import java.util.concurrent.Callable;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;
import java.util.concurrent.TimeUnit;
import java.util.concurrent.TimeoutException;
public class TimeOutTest {
public static void main(String[] args) {
System.out.println("程序开始");
final ExecutorService exec = Executors.newFixedThreadPool(1);
Callable<String> call = new Callable<String>() {
public String call() throws Exception {
// 开始执行耗时操作
Thread.sleep(1000 * 3);
System.out.println("程序早结束了，已经没用了。");
return "线程执行完成.";
}
};
Future<String> future = null;
try {
future = exec.submit(call);
String obj = future.get(1000 * 1, TimeUnit.MILLISECONDS); // 任务处理超时时间设为 1 秒
System.out.println("任务成功返回:" + obj);
} catch (TimeoutException ex) {
System.out.println("处理超时啦....");
if(future!=null){
future.cancel(true);
}
} catch (Exception e) {
System.out.println("处理失败.");
}finally{
System.out.println("关闭线程池");
// 关闭线程池
exec.shutdown();
}
System.out.println("程序结束");
}
}
