Morris遍历

import java.util.ArrayList;
import java.util.List;

// https://www.nowcoder.com/questionTerminal/a9fec6c46a684ad5a3abd4e365a9d362
public class Solution {

    private static int[] toArray(List<TreeNode> nodes) {
        if (nodes == null || nodes.size() == 0) {
            return new int[0];
        }
        int[] result = new int[nodes.size()];
        for (int i = 0; i < result.length; ++i) {
            result[i] = nodes.get(i).val;
        }
        return result;
    }

    /**
     * @param root TreeNode类 the root of binary tree
     * @return int整型二维数组
     */
    public static int[][] threeOrders(TreeNode root) {
        // write code here

        int[][] result = new int[3][];

        List<TreeNode> nodes = PreOrder.solve(root);
        result[0] = toArray(nodes);

        nodes = MidOrder.solve(root);
        result[1] = toArray(nodes);

        nodes = PostOrder.solve(root);
        result[2] = toArray(nodes);

        return result;
    }
}

class TreeNode {
    int val = 0;
    TreeNode left = null;
    TreeNode right = null;
}

class PreOrder {

    /**
     * 两种情况
     * 1. 没有左子树
     * 2. 第一次来到这个节点的时候（mostRight指向null）
     *
     * @param root
     * @return
     */
    public static List<TreeNode> solve(TreeNode root) {
        if (root == null) {
            return new ArrayList<>(0);
        }

        List<TreeNode> result = new ArrayList<>();
        TreeNode cur = root, mostRight;
        while (cur != null) {
            mostRight = cur.left;
            if (mostRight != null) {
                while (mostRight.right != null && mostRight.right != cur) {
                    mostRight = mostRight.right;
                }

                if (mostRight.right == null) {
                    result.add(cur);
                    mostRight.right = cur;
                    cur = cur.left;
                    continue;
                } else {
                    mostRight.right = null;
                }
            } else {
                result.add(cur);
            }
            cur = cur.right;
        }
        return result;
    }
}

class MidOrder {

    /**
     * 两种情况
     * 1. 没有左子树
     * 2. 第二次来到这个节点的时候（mostRight指向cur）
     *
     * @param root
     * @return
     */
    public static List<TreeNode> solve(TreeNode root) {
        if (root == null) {
            return new ArrayList<>(0);
        }

        List<TreeNode> result = new ArrayList<>();
        TreeNode cur = root, mostRight;
        while (cur != null) {
            mostRight = cur.left;
            if (mostRight != null) {
                while (mostRight.right != null && mostRight.right != cur) {
                    mostRight = mostRight.right;
                }

                if (mostRight.right == null) {
                    mostRight.right = cur;
                    cur = cur.left;
                    continue;
                } else {
                    mostRight.right = null;
                }
            }
            result.add(cur);
            cur = cur.right;
        }
        return result;
    }
}

class PostOrder {

    private static TreeNode reverse(TreeNode head) {
        if (head == null) {
            return head;
        }
        TreeNode pre = null, cur = head, next;
        while (cur != null) {
            next = cur.right;
            cur.right = pre;
            pre = cur;
            cur = next;
        }
        return pre;
    }

    /**
     * 能回到两次，且第二次回到的时候，取左树右边界
     *
     * @param root
     * @return
     */
    public static List<TreeNode> solve(TreeNode root) {
        if (root == null) {
            return new ArrayList<>(0);
        }

        List<TreeNode> result = new ArrayList<>();
        TreeNode cur = root, mostRight;
        while (cur != null) {
            mostRight = cur.left;
            if (mostRight != null) {
                while (mostRight.right != null && mostRight.right != cur) {
                    mostRight = mostRight.right;
                }

                if (mostRight.right == null) {
                    mostRight.right = cur;
                    cur = cur.left;
                    continue;
                } else {
                    mostRight.right = null;
                    result.addAll(getRightEdge(cur.left));
                }
            }
            cur = cur.right;
        }
        result.addAll(getRightEdge(root));
        return result;
    }

    private static List<TreeNode> getRightEdge(TreeNode head) {
        if (head == null) {
            return new ArrayList<>(0);
        }
        List<TreeNode> result = new ArrayList<>();
        TreeNode tail = reverse(head);
        head = tail;

        while (head != null) {
            result.add(head);
            head = head.right;
        }
        reverse(tail);
        return result;
    }
}

心之所向，素履以往 生如逆旅，一苇以航