314. Binary Tree Vertical Order Traversal /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { class Pair{ TreeNode node; Integer pos; public Pair(TreeNode node, Integer pos){ this.node = node; this.pos = pos; } } public List<List<Integer>> verticalOrder(TreeNode root) { HashMap<Integer, List<Integer>> map = new HashMap<>(); List<List<Integer>> result = new ArrayList<>(); if(root == null){ return result; } Queue<Pair> queue = new LinkedList<>(); Integer max = 0; Integer min = 0; queue.offer(new Pair(root, 0)); while(!queue.isEmpty()){ Pair cur = queue.poll(); Integer curPos = cur.pos; TreeNode curNode = cur.node; if(!map.containsKey(curPos)){ map.put(curPos, new ArrayList<>()); } map.get(curPos).add(curNode.val); if(curNode.left != null){ min = Math.min(min, curPos - 1); queue.offer(new Pair(curNode.left, curPos - 1)); } if(curNode.right != null){ max = Math.max(max, curPos + 1); queue.offer(new Pair(curNode.right, curPos + 1)); } } for(int i = min; i <= max; i++){ result.add(map.get(i)); } return result; } }
use two stacks
314. Binary Tree Vertical Order Traversal class Solution { public List<List<Integer>> verticalOrder(TreeNode root) { HashMap<Integer, List<Integer>> map = new HashMap<>(); List<List<Integer>> result = new ArrayList<>(); Queue<TreeNode> queue = new LinkedList<>(); Queue<Integer> cols = new LinkedList<>(); if(root == null){ return result; } int max = 0; int min = 0; queue.offer(root); cols.offer(0); while(!queue.isEmpty()){ TreeNode cur = queue.poll(); int col = cols.poll(); if(!map.containsKey(col)){ map.put(col, new ArrayList<Integer>()); } map.get(col).add(cur.val); if(cur.left != null){ queue.offer(cur.left); cols.offer(col - 1); min = Math.min(min, col - 1); } if(cur.right != null){ queue.offer(cur.right); cols.offer(col + 1); max = Math.max(max, col + 1); } } for(int i = min; i <= max; i++){ List<Integer> current_col = map.get(i); result.add(current_col); } return result; } }