强连通分量之间权值为0
强连通加最短路


//#include<bits/stdc++.h> #include<iostream> #include<cstring> #include<cstdio> using namespace std; //input by bxd #define rep(i,a,b) for(int i=(a);i<=(b);i++) #define repp(i,a,b) for(int i=(a);i>=(b);--i) #define RI(n) scanf("%d",&(n)) #define RII(n,m) scanf("%d%d",&n,&m) #define RIII(n,m,k) scanf("%d%d%d",&n,&m,&k) #define RS(s) scanf("%s",s); #define ll long long #define pb push_back #define REP(i,N) for(int i=0;i<(N);i++) #define CLR(A,v) memset(A,v,sizeof A) ////////////////////////////////// #define inf 0x3f3f3f3f const int N=500+5; const int M=N*N; int head[M],pos; struct Edge { int nex,to,v; }edge[M]; struct node { int s,e,v; }s[M]; void add(int a,int b,int c) { edge[++pos].nex=head[a]; head[a]=pos; edge[pos].v=c; edge[pos].to=b; } int tot,ind,cnt,Stack[N],dfn[N],low[N],vis[N],belong[N]; int dis[N]; int mp[N][N]; int n,m; void init() { tot=ind=cnt=pos=0; CLR(Stack,0); CLR(head,0); CLR(vis,0); CLR(dfn,0); CLR(low,0); rep(i,1,n) rep(j,1,n) if(i!=j)mp[i][j]=inf; else mp[i][j]=0; } void tarjan(int x) { dfn[x]=low[x]=++tot; Stack[++ind]=x; vis[x]=1; for(int i=head[x];i;i=edge[i].nex) { int v=edge[i].to; if(!dfn[v]) { tarjan(v); low[x]=min(low[x],low[v]); } else if(vis[v]) low[x]=min(low[x],low[v]); } if(dfn[x]==low[x]) { cnt++;int v; do { v=Stack[ind--]; vis[v]=0; belong[v]=cnt; } while(x!=v); } } int main() { while(RII(n,m),n||m) { init(); rep(i,1,m) { int a,b,c;RIII(a,b,c); add(a,b,c); } rep(i,1,n) if(!dfn[i])tarjan(i); rep(i,1,n) { int u=belong[i]; for(int j=head[i];j;j=edge[j].nex) { int v=belong[ edge[j].to ]; if(u!=v) { mp[u][v]=min(mp[u][v],edge[j].v); } } } int k; RI(k); int last=-1; while(k--) { int a,b; RII(a,b); a=belong[a]; b=belong[b]; if(a==last) { if(dis[b]==inf) printf("Nao e possivel entregar a carta\n"); else printf("%d\n",dis[b]); } else { last=a; rep(i,1,cnt) dis[i]=inf; dis[a]=0; CLR(vis,0); while(1) { int u=-1,minn=inf; rep(i,1,cnt) if(!vis[i]&&dis[i]<minn) minn=dis[u=i]; if(u==-1)break; vis[u]=1; rep(i,1,cnt) dis[i]=min(dis[i],dis[u]+mp[u][i]); } if(dis[b]==inf) printf("Nao e possivel entregar a carta\n"); else printf("%d\n",dis[b]); } } cout<<endl; } return 0; }