为简化问题:

设表:t(id int, col2 varchar(32))

 

1. ASE:

 

选出重复的行:

select * from t group by id, col2 having count(*)>1

删掉重复的行,

alter table t add col3 int identity not null;

delete from t where col3 not in (select max(col3) from t group by id, col2);

alter table t drop col3;  (前提select into/bulkcopy on数据库上的options)

 

2. ASA: (设表t123)

 

select * from t123

id,col2

1,'a'

1,'a'

2,'b'

3,'c'

delete from t123 where col3 not in (select max(col3) from t123 group by id, col2);

alter table t123 drop col3;

 

上述方法对ASE和ASA基本上是一样的。除了ASE中要求目标数据库select into为ON

 

3. ORACLE:

大概有两种方法:

方法1:基于rowid

delete from t a

where a.rowid !=

(

select max(b.rowid) from t b

where a.id = b.id and

a.col2 = b.col2

)

SQL> select * from t; ID COL2 ---------- -------------------------------- 1 a 1 a 2 b 3 c SQL> delete from t a where a.rowid != (select max(b.rowid) from t b where a.id=b.id and a.col2 = b.col2); 已删除 1 行。 SQL> select * from t; ID COL2 ---------- -------------------------------- 1 a 2 b 3 c

 

 

方法2:使用临时表

SQL> select * from t; ID COL2 ---------- -------------------------------- 1 a 2 b 3 c SQL> insert into t values(1, 'a'); 已创建 1 行。 SQL> create table tt as select t.id, t.col2, max(t.rowid) dataid from t group by t.id, t.col2; 表已创建。 SQL> delete from t a where a.rowid != (select b.dataid from tt b where a.id=b.id and a.col2=b.col2); 已删除 1 行。 SQL> select * from t; ID COL2 ---------- -------------------------------- 2 b 3 c 1 a

 

相信ASE/ASA也可以使用临时表的方案。(表特别大的时候,也许很有用)

 

至于MySQL/DB2当中的方法,应该是很类似的。不再赘述。