C++

 

#include<iostream>
using namespace std;

int main()
{
 int a,b;
 while(cin>>a>>b)
  cout<<a+b<<endl;
 return 1;
}
 
C
 
 #include<stdio.h>
 #define P 3.1415927
 main()
 {
     int a,b;
     while(scanf("%d%d",&a,&b)==2)
        printf("%d\n",a+b);
     return 0;
 }
 
Java
 

import java.util.Scanner;

public class Main{
 public static void main(String[] args) {
  Scanner in = new Scanner(System.in);
  while (in.hasNextInt()) {
   int a = in.nextInt();
   int b = in.nextInt();
   System.out.println(a + b);
  }
 }
}

 
 
 
 
 
 
 
 

解题报告：

循环语句

代码：

  1. #include<stdio.h>
  2. main()
  3. {
  4.     int a,b;
  5.     while(scanf("%d%d",&a,&b)!=EOF)
  6.     {
  7.         printf("%d\n",a+b);
  8.     }
  9.     return 0;
  10. }

Description

Calculate a+b

Input

Two integer a,b (0<=a,b<=10)

Output

Output a+b

SampleInput

1 2

SampleOutput

Q: Where are the input and the output?

A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout.

You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer".

User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer"if you try to do so.

Here is a sample solution to problem 1000 using C++/G++:

#include  using namespace std; int main() { int a,b; cin >> a >> b; cout << a+b << endl; return 0; } It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error. Here is a sample solution to problem 1000 using C/GCC: #include  int main() { int a,b; scanf("%d %d",&a, &b); printf("%d\n",a+b); return 0; } Here is a sample solution to problem 1000 using Pascal: program p1000(Input,Output); var a,b:Integer; begin Readln(a,b); Writeln(a+b); end. Here is a sample solution to problem 1000 using Java: Now java compiler is jdk 1.5, next is program for 1000 import java.io.*; import java.util.*; public class Main { public static void main(String args[]) throws Exception { Scanner cin=new Scanner(System.in); int a=cin.nextInt(),b=cin.nextInt(); System.out.println(a+b); } } Old program for jdk 1.4 import java.io.*; import java.util.*; public class Main { public static void main (String args[]) throws Exception { BufferedReader stdin = new BufferedReader( new InputStreamReader(System.in)); String line = stdin.readLine(); StringTokenizer st = new StringTokenizer(line); int a = Integer.parseInt(st.nextToken()); int b = Integer.parseInt(st.nextToken()); System.out.println(a+b); } } Here is a sample solution to problem 1000 using Fortran: PROGRAM P1000 IMPLICIT NONE INTEGER :: A, B READ(*,*) A, B WRITE(*, "(I0)") A + B END PROGRAM P1000

Hint

Q: Where are the input and the output?

A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout.

You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer".

User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer"if you try to do so.

Here is a sample solution to problem 1000 using C++/G++:

#include  using namespace std; int main() { int a,b; cin >> a >> b; cout << a+b << endl; return 0; } It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error. Here is a sample solution to problem 1000 using C/GCC: #include  int main() { int a,b; scanf("%d %d",&a, &b); printf("%d\n",a+b); return 0; } Here is a sample solution to problem 1000 using Pascal: program p1000(Input,Output); var a,b:Integer; begin Readln(a,b); Writeln(a+b); end. Here is a sample solution to problem 1000 using Java: Now java compiler is jdk 1.5, next is program for 1000 import java.io.*; import java.util.*; public class Main { public static void main(String args[]) throws Exception { Scanner cin=new Scanner(System.in); int a=cin.nextInt(),b=cin.nextInt(); System.out.println(a+b); } } Old program for jdk 1.4 import java.io.*; import java.util.*; public class Main { public static void main (String args[]) throws Exception { BufferedReader stdin = new BufferedReader( new InputStreamReader(System.in)); String line = stdin.readLine(); StringTokenizer st = new StringTokenizer(line); int a = Integer.parseInt(st.nextToken()); int b = Integer.parseInt(st.nextToken()); System.out.println(a+b); } } Here is a sample solution to problem 1000 using Fortran: PROGRAM P1000 IMPLICIT NONE INTEGER :: A, B READ(*,*) A, B WRITE(*, "(I0)") A + B END PROGRAM P1000