内容概要:

满足下面3个条件时,

1. 父类有虚函数,子类也有虚函数,且子类的虚函数重写或覆盖了父类的虚函数

2. 非虚继承

3. 多重继承

类对象之内存布局

多重继承,派生类不重写基类中的虚函数。

假定各类之间的关系如下图:

   

代码如下:



#include <iostream>
using namespace std;

class Base1
{
public:
int m_base1;
inline virtual void vfBase1_1()
{
cout << "This is in Base1::vfBase1_1()" << endl;
}
inline virtual void vfBase1_2()
{
cout << "This is in Base1::vfBase1_2()" << endl;
}
};
class Base2
{
public:
int m_base2;
inline virtual void vfBase2_1()
{
cout << "This is in Base2::vfBase2_1()" << endl;
}
inline virtual void vfBase2_2()
{
cout << "This is in Base2::vfBase2_2()" << endl;
}
};
class Base3
{
public:
int m_Base3;
inline virtual void vfBase3_1()
{
cout << "This is in Base3::vfBase3_1()" << endl;
}
inline virtual void vfBase3_2()
{
cout << "This is in Base3::vfBase3_2()" << endl;
}
};
class Derived : public Base1, public Base2, public Base3
{
public:
int m_derived;
inline virtual void fd()
{
cout << "This is in Derived::fd()" << endl;
}
};
typedef void (*VFun)(void);
template<typename T>
VFun virtualFunctionPointer(T* b, int i)
{
return (VFun)(*((int*)(*(int*)b) + i));
}
int main(void)
{
Derived d;
cout << "The size of Derived object = \t" << sizeof(Derived) << endl;
cout << endl;
cout << "1st virtual function table: " << endl;
int i = 0;
while(virtualFunctionPointer(&d, i)&&i<3)
{
VFun pVF = virtualFunctionPointer(&d, i++);
pVF();
}
cout << endl;
cout << "2nd virtual function table: " << endl;
i = 0;
//以32字长的机器,找到下一个继承base class的vptr
int* tmp = ((int*)&d)+ sizeof(Base1)/4;
//虚函数表中的虚函数后面不为NULL?如果不加i的限制会出现段错误,不能结束循环
while(virtualFunctionPointer(tmp, i)&&i<2)

{
VFun pVF = virtualFunctionPointer(tmp, i++);
pVF();
}
cout << endl;
cout << "3rd virtual function table: " << endl;
i = 0;
tmp = ((int*)&d) +(sizeof(Base1)+sizeof(Base2))/4;
while(virtualFunctionPointer(tmp, i)&&i<2)
{
VFun pVF = virtualFunctionPointer(tmp, i++);
pVF();
}
return 0;
}


运行结果:

对象内存布局 (5)_虚函数


 

(表中的Base::vfBase1_1应该是Base1::vfBase1_1,其余的类推)

由上面的分析可知:

其一:有三个虚函数表

其二:在Derived类中定义的虚函数Derived::vfDerived()附加在一个虚函数表的最后

 (注意:多重继承有多个虚函数表)