将下列对象数组,通过工资属性,由高到低排序
var BaiduUsers = [], WechatUsers = [];
var User = function(id, name, phone, gender, age, salary) {
this.id = id;
this.name = name;
this.phone = phone;
this.gender = gender;
this.age = age;
this.salary = salary;
};
User.create = function(id, name, phone, gender, age, salary) {
return new User(id, name, phone, gender, age, salary);
};
BaiduUsers.push(User.create(1, 'tommy', '1111','male', 18, 2800));
BaiduUsers.push(User.create(2, 'jerry', '2222','male', 28, 5800));
BaiduUsers.push(User.create(3, 'raobin','3333','female', 14, 1200));
BaiduUsers.push(User.create(4, 'binbin','4444','male', 23, 9800));
BaiduUsers.push(User.create(5, 'arthur','5555','female', 22, 3000));
WechatUsers.push(User.create(1, 'tommy', '1111','male', 20, 4000));
WechatUsers.push(User.create(2, 'allen', '6666','male', 34, 15800));
WechatUsers.push(User.create(3, 'raobin','3333','female', 16, 2300));
WechatUsers.push(User.create(4, 'harvey','7777','male', 30, 29800));
WechatUsers.push(User.create(5, 'yuyu', '8888','female', 27, 7000));
对于一般的数组,可以用sort函数,对于对象数组呢
var points = [40,100,1,5,25,10];
points.sort(function(a,b){return a-b});
那么考点在哪里呢?实际上在于数组对象的sort方法。
Array.sort(fun)
fun是一个函数,排序根据这个函数返回值来进行判断,如果返回值小于0表示两个元素不需要交换位置,1表示要用交互位置,0表示相等,实际上<=0等效。
sort方法有两个注意点:
会操作原始数组,经过操作后原始数组发生变化
需要定义下sortBy方法,然后进行调用即可
BaiduUsers.sort(sortBy("salary"))
如果存在工资相等的情况,要求按照年纪排序,应该如何定义SortBY方法呢?
var BaiduUsers = [], WechatUsers = [];
var User = function(id, name, phone, gender, age, salary) {
this.id = id;
this.name = name;
this.phone = phone;
this.gender = gender;
this.age = age;
this.salary = salary;
};
User.create = function(id, name, phone, gender, age, salary) {
return new User(id, name, phone, gender, age, salary);
};
BaiduUsers.push(User.create(1, 'tommy', '1111','male', 18, 10000));
BaiduUsers.push(User.create(2, 'jerry', '2222','male', 28, 10000));
BaiduUsers.push(User.create(3, 'raobin','3333','female', 14, 1200));
BaiduUsers.push(User.create(4, 'binbin','4444','male', 23, 9800));
BaiduUsers.push(User.create(5, 'arthur','5555','female', 22, 10000));
function sortBy(field1,field2) {
return function(a,b) {
if(a.field1 == b.field1) return a.field2 - b.field2;
return a.field1 - b.field1;
}
}
BaiduUsers.sort(sortBy("salary","age"));
貌似不正确ing
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