[USACO 2009 Dec S]Music Notes

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whiteawll 2022-08-16 14:40:53 博主文章分类：练习题目 ©著作权

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// Problem: [USACO 2009 Dec S]Music Notes
// Contest: NowCoder
// URL: https://ac.nowcoder.com/acm/contest/22353/A
// Memory Limit: 65536 MB
// Time Limit: 2000 ms
// 2022-04-17 22:12:14
// 
// Powered by CP Editor (https://cpeditor.org)

#include<bits/stdc++.h>
using namespace std;

#define rep(i,l,r) for(int i=(l);i<=(r);i++)
#define per(i,l,r) for(int i=(l);i>=(r);i--)
#define ll long long
#define mset(s,t) memset(s,t,sizeof(t))
#define mcpy(s,t) memcpy(s,t,sizeof(t))
#define fi first
#define se second
#define pb push_back
#define all(x) (x).begin(),(x).end()
#define SZ(x) ((int)(x).size())
#define mp make_pair

typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;   
typedef vector<ll> Vll;               
typedef vector<pair<int, int> > vpii;
typedef vector<pair<ll, ll> > vpll;                        

const ll mod = 1e9 + 7;
//const ll mod = 998244353;
const double pi  = acos(-1.0);
inline ll ksc(ll x,ll y,ll mod)
{
    ll ans = 0;
    while (y) {
        if (y & 1)
            ans = (ans + x) %mod;
        y >>= 1;
        x = (x + x) %mod;
    }
    return ans;
}
inline ll qmi (ll a, ll b) {
    ll ans = 1;
    while (b) {
        if (b & 1) ans = ans * a;
        a = a * a;
        b >>= 1;
    }
    return ans;
}
inline int read () {
    int x = 0, f = 0;
    char ch = getchar();
    while (!isdigit(ch)) f |= (ch=='-'),ch= getchar();
    while (isdigit(ch)) x = x * 10 + ch - '0', ch = getchar();
    return f?-x:x;
}
template<typename T> void print(T x) {
    if (x < 0) putchar('-'), x = -x;
    if (x >= 10) print(x/10);
    putchar(x % 10 + '0');
}
inline ll sub (ll a, ll b) {
    return ((a - b ) %mod + mod) %mod;
}
inline ll add (ll a, ll b) {
    return (a + b) %mod;
}
// inline ll inv (ll a) {
    // return qmi(a, mod - 2);
// }
 int n, q;

void solve() {
    
    cin >> n >> q;
    vector<int> b(n + 1, 0);
    for (int i = 1; i <= n; i ++)
        cin >> b[i];
    for (int i = 1; i <= n; i ++)
            b[i] += b[i - 1];
    while (q --) {
        int x;
        cin >> x;
        int l = 1, r = n;
        while (l < r) {
            int mid = l + r>> 1;
            bool f = 0;
            if ( b[mid] > x)
                f = 1;
            if (f){
                r = mid;
                
            }
            else l = mid + 1;
        }   
       cout << l << endl;
    }
}
int main () {
    // ios::sync_with_stdio(0),cin.tie(0), cout.tie(0);
    int t;
    t =1;
    //cin >> t;
    while (t --) solve();
    return 0;
}