不太会改进

思路:
把输入的两个二维数组换为两个一维数组,非零数字对应,无则补0;
最后这两个一维数组的对应下标相乘

package _2_17_稀疏向量_60;

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		
		Scanner scanner = new Scanner(System.in);
		
		int weiShu = scanner.nextInt();
		int n1 = scanner.nextInt();
		int n2 = scanner.nextInt();
		
		int[] a = new int[weiShu];
		int[] b = new int[weiShu];
		
		
		//分别给两个数组赋值
		for (int i = 0; i < weiShu; i++) {
			a[i] = 0;
			b[i] = 0;
		}
		
		int[][] martix1 = new int[n1][2];
		int[][] martix2 = new int[n2][2];
		
		for (int i = 0; i < martix1.length; i++) {
			for (int j = 0; j < martix1[0].length; j++) {
				martix1[i][j] = scanner.nextInt();
			}
		}
		
		for (int i = 0; i < martix2.length; i++) {
			for (int j = 0; j < martix2[0].length; j++) {
				martix2[i][j] = scanner.nextInt();
			}
		}
		
		for(int i = 0; i < martix1.length; i++){
			a[martix1[i][0]-1] = martix1[i][1];
		}
		
		for (int i = 0; i < martix2.length; i++) {
			b[martix2[i][0]-1] = martix2[i][1];
		}
		
		long sum = 0;
		for (int i = 0; i < weiShu; i++) {
			sum += (a[i]*b[i]);
		}
		System.out.println(sum);
		
	}
}