我的一种思路是递归:
private static String s = "(2344[)]53[234]{2324}";
private static boolean f(int x, int y) {
for (int i = x; i < s.length(); i++) {
if (s.charAt(i) == '(') {
return f(i + 1, 1);
} else if (s.charAt(i) == '[') {
return f(i + 1, 2);
} else if (s.charAt(i) == '{') {
return f(i + 1, 3);
} else if (s.charAt(i) == ')') {
return y == 1;
} else if (s.charAt(i) == ']') {
return y == 2;
} else if (s.charAt(i) == '}') {
return y == 3;
}
}
return true;
}
public static void main(String[] args) {
System.out.println(f(0,0));
}