python 矩阵相等 python矩阵相乘代码_线性代数

求矩阵A*B,得到的结果C

得到矩阵C

A=[[1,1,1],[2,2,2],[3,3,3]]
B=[[1,0,0],[0,1,0],[0,0,1]]
c=[[0,0,0],[0,0,0],[0,0,0]]
for i in range(3):
    for j in range(3):
        for k in range(3):
            c[i][j] += A[i][k]*B[k][j]

输出矩阵C

for i in range(3):
    for j in range(3):
        if (j+1)%3 == 0 and (i+1)%3 != 0:
            print(c[i][j],end=' ')
            print()
            continue
        print(c[i][j],end=' ')

python 矩阵相等 python矩阵相乘代码_python_02