Andorid 3种Json解析框架简单示例

1.使用Jackson 框架，轻易转换JSON:
示例：

try {
                ObjectMapper objectMapper = new ObjectMapper();
                StringWriter sw = new StringWriter();
                JsonGenerator generator = objectMapper.getJsonFactory().createJsonGenerator(sw);
                generator.writeObject(new Person(1, "tom" ,20));
                generator.close();
                return sw.toString();
            } catch (IOException e) {
                e.printStackTrace();
        }

2.使用Gson框架

3.Android系统自带的

public List<Area> getRemoteAreas(String keyword) throws Exception {
        List<Area> areaList = new ArrayList<Area>();
        String returnValue = queryUtils.queryServer(keyword, "queryarea", "ServiceDocumentServlet");
        if (returnValue != null && !"".equals(returnValue)) {
            JSONArray jsonArray = new JSONArray(returnValue);
            if (jsonArray != null) {
                JSONObject jsonObject;
                Area area = null;
                // 循环记录数（多少条）
                for (int i = 0; i < jsonArray.length(); i++) {
                    area = new Area();
                    jsonObject = jsonArray.getJSONObject(i);
                    if (jsonObject != null) {
                        area.setId(jsonObject.getString("areaId"));
                        area.setSname(jsonObject.getString("areaName"));
                        area.setParent(jsonObject.getString("areaParent"));
                        area.setpId(jsonObject.getString("areaPId"));
                        areaList.add(area);
                    }
                }
            }
        }
        return areaList;
    }