题目链接:点击打开链接


题解思路:我们枚举公比跟首项然后比较是否跟"xry"或"yrx"匹配就行了.


代码:

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int mx = 1e4+10;
int n,a,b;
char str[mx],c[mx];
const char s[2][4] = {"yrx","xry"};
bool check(char *p)
{
    for(int i=0;i<2;i++)
    if(!strcmp(p,s[i])) return 1;
    return 0;
}
int main()
{
    int t;
    scanf("%d",&t);
    //freopen("1in","r",stdin);
    while(t--){
        char ch;
        scanf("%s",str+1);
        int ans = 0;
        int len = strlen(str+1);
        c[3] = 0;
        for(int i=2;i*i<=len;i++){
            for(int j=1;j*i*i<=len;j++){
                c[0] = str[j];
                c[1] = str[j*i];
                c[2] = str[j*i*i];
                if(check(c)) ans++;
            }
        }
        printf("%d\n",ans);
    }
    return 0;
}