1. 题目
给出一个字符串数组words组成的一本英语词典。从中找出最长的一个单词,该单词是由words词典中其他单词逐步添加一个字母组成。若其中有多个可行的答案,则返回答案中字典序最小的单词。
若无答案,则返回空字符串。
示例 1:
输入:
words = ["w","wo","wor","worl", "world"]
输出:"world"
解释:
单词"world"可由"w", "wo", "wor", 和 "worl"添加一个字母组成。
示例 2:
输入:
words = ["a", "banana", "app", "appl", "ap", "apply", "apple"]
输出:"apple"
解释:
"apply"和"apple"都能由词典中的单词组成。但是"apple"的字典序小于"apply"。
提示:
所有输入的字符串都只包含小写字母。
words数组长度范围为[1,1000]。
words[i]的长度范围为[1,30]。
2. 题解
# 720
import collections
from typing import List
class Node:
def __init__(self):
self.children = collections.defaultdict(Node)
self.isword = False
class Trie:
def __init__(self):
self.root = Node()
def insert(self, word: str):
cur = self.root
for w in word:
cur = cur.children[w]
cur.isword = True
def search(self, word: str) -> bool:
cur = self.root
for w in word:
cur = cur.children.get(w)
if cur is None or not cur.isword:
return False
return cur.isword
class Solution:
def longestWord(self, words: List[str]) -> str:
res = ""
trie = Trie()
for word in words:
trie.insert(word)
for word in words:
if trie.search(word):
if len(word) > len(res):
res = word
elif len(word) == len(res) and word < res:
res = word
return