asp.net post提交参数 .net post请求

1.定义一个POST 公共方法 

///HttpWebRequest的POST请求的类型通常有application/x-www-form-urlencoded、application/json、multipart/form-data。
        ///application/x-www-form-urlencoded是默认的请求类型。
        ///application/json是Json数据格式的请求类型。
        ///multipart/form-data是表单数据的请求类型。
        ///以上三种方式中，multipart/form-data通常用于文件上传。
        /// <summary>
        /// JSON请求API
        /// </summary>
        /// <param name="url">地址</param>
        /// <param name="jsonStr">JSON字符串</param>
        /// <returns></returns>
        public static string Post(string url, string jsonStr)
        {
            string result = "";
            HttpWebRequest req = (HttpWebRequest)WebRequest.Create(url);
            req.Method = "POST";
            //req.ContentType = "application/x-www-form-urlencoded";
            req.ContentType = "application/json";
            //req.Headers.Add("Authorization", "PoJzmqZHM@CmitMCcl8@vIQSL&ro$Kq8");
            #region 添加Post 参数
            byte[] data = Encoding.UTF8.GetBytes(jsonStr);
            req.ContentLength = data.Length;
            using (Stream reqStream = req.GetRequestStream())
            {
                reqStream.Write(data, 0, data.Length);
                reqStream.Close();
            }
            #endregion
            HttpWebResponse resp = (HttpWebResponse)req.GetResponse();
            Stream stream = resp.GetResponseStream();
            //获取响应内容
            using (StreamReader reader = new StreamReader(stream, Encoding.UTF8))
            {
                result = reader.ReadToEnd();
            }
            return result;
        }

 2.直接调用 url地址改成你对应API的地址Get4是对应下面API的名称

/// <summary>
        /// 测试方法
        /// </summary>
        public void test()
        {
            string url = "https://localhost:7049/WeatherForecast/Get4";
            string jsonRequest = JsonConvert.SerializeObject(new List<test> { new test { name = "测试名称" } });
            var result = Post(url, jsonRequest);
        }

3..API接口设置（这里采用的是.net core 6 API 的默认接口）

[HttpPost(Name = "Get4")]
        public IActionResult Get4([FromBody]List<test> test)
        {
            return new JsonResult(test);
        }