字典树

​百度百科​​​ 大概是一个26叉树
插入
每次插入的时候如果当前没有这个分支就新建节点

查找
每次查找都从根节点开始,随着单词的前后顺序如果一直可以查到尾巴
那么就证明存在

为了和前缀区分
为每一个单词后面加一个"}"

因为’}'的ascii码是’z’的下一个

#include <iostream>
#include <map>
#include <stdio.h>

using namespace std;

#define debug(x) cout<<#x<<": "<<(x)<<endl;

class Trie {
public:
/** Initialize your data structure here. */

struct node{
char c;
node* children[27] = {nullptr};
node():c('0'){}
node(char c):c(c){}
};

node * root;
Trie() {
root = new node('0');
}

/** Inserts a word into the trie. */
void insert(string word) {
word+= "{";
node * t = root;
for(int i = 0;i < word.size();i ++){
if(t->children[word[i] - 'a']== nullptr){
t->children[word[i] - 'a'] = new node(word[i]);
}
t = t->children[word[i] - 'a'];
}
}

/** Returns if the word is in the trie. */
bool search(string word) {
word+= "{";
node * t = root;
for(int i = 0;i < word.size();i ++){
if(t->children[word[i] - 'a']== nullptr){
return false;
}
if(t->children[word[i] - 'a']->c != word[i]){
return false;
}
t = t->children[word[i] - 'a'];
}
return true;
}

/** Returns if there is any word in the trie that starts with the given prefix. */
bool startsWith(string prefix) {

node * t = root;
for(int i = 0;i < prefix.size();i ++){
if(t->children[prefix[i] - 'a'] == nullptr){
return false;
}

if(t->children[prefix[i] - 'a']->c != prefix[i]){
return false;
}
t = t->children[prefix[i] - 'a'];
}
return true;
}
};

/**
* Your Trie object will be instantiated and called as such:
* Trie* obj = new Trie();
* obj->insert(word);
* bool param_2 = obj->search(word);
* bool param_3 = obj->startsWith(prefix);
*/

int main()
{
Trie t;
t.insert("apple");
debug(t.search("apple"));
debug(t.search("app"));
debug(t.startsWith("app"));

t.insert("app");
debug(t.search("apple"));
debug(t.search("app"));
debug(t.startsWith("app"));
return 0;
}

leetcode 208. 实现 Trie (前缀树)-字典树_#include