给定一个包含 m x n 个元素的矩阵(m 行, n 列),请按照顺时针螺旋顺序,返回矩阵中的所有元素。
示例 1:
输入:
[
[ 1, 2, 3 ],
[ 4, 5, 6 ],
[ 7, 8, 9 ]
]
输出: [1,2,3,6,9,8,7,4,5]
示例 2:
输入:
[
[1, 2, 3, 4],
[5, 6, 7, 8],
[9,10,11,12]
]
输出: [1,2,3,4,8,12,11,10,9,5,6,7]
class Solution {
public:
vector<int> spiralOrder(vector<vector<int>>& matrix) {
if (matrix.empty() || matrix[0].empty())
return {};
int left = 0, right = matrix[0].size() - 1, top = 0, bottom = matrix.size() - 1;
vector<int> res;
int i = 0, j = 0;
while (true)
{
if (j > right)
break;
while (j <= right)
res.push_back(matrix[i][j++]);
top++;
i++;
j = right;
if (i > bottom)
break;
while (i <= bottom)
res.push_back(matrix[i++][j]);
right--;
j--;
i = bottom;
if (j < left)
break;
while (j >= left)
res.push_back(matrix[i][j--]);
bottom--;
i--;
j = left;
if (i < top)
break;
while (i >= top)
res.push_back(matrix[i--][j]);
left++;
j++;
i = top;
}
return res;
}
};